Question

Solve the following equations by hit and trial method:

$\mathrm{x}-3=8$

Answer 1

Given equation: $\mathrm{x}-3=8$

The side on the left of this equal sign $(=)$ is called the left hand side (or L.H.S.) and the one on the right is called the right hand side (or R.H.S.)

so, here L.H.S $=$$\mathrm{x}-3$ and R.H.S $=8$

By looking at the given equation we can easily understand that number $\mathrm{x}$ will be greater than $8$ (because as we are getting $8$ as a result after subtracting $3$ from it. So we should try numbers greater then $8$.

Now try $\mathrm{x}=9,10,11,12...$

When, $\mathrm{x}=9$ L.H.S $=9-3=6\ne$R.H.S

When, $\mathrm{x}=10$ L.H.S $=10-3=7\ne$R.H.S

When, $\mathrm{x}=11$ L.H.S $=11-3=8=$R.H.S

Hence, $\mathrm{x}=11$ is the solution.