Solve the following equations by substitution method.
$x = 2 y - 1; y = 2 x - 7$

x = 8, y = 3

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x = 2, y = 3

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x = 5, y = 3

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x = 1, y = 3

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Solution

The correct option is C $x = 5, y = 3$
$x = 2 y - 1; y = 2 x - 7$
$x = 2 y - 1$ Put it in second equation.
$y = 2 \times (2 y - 1) - 7$
$y = 4 y - 9$
$y = 3$
and
$x = 2 y - 1 = 2 \times 3 - 1 = 5$
$x = 5$
$x = 5 a n d y = 3$

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Solve the following equations by substitution method.x=2y−1;y=2x−7

The correct option is C x=5,y=3x=2y−1;y=2x−7x=2y−1 Put it in second equation.y=2×(2y−1)−7y=4y−9y=3andx=2y−1=2×3−1=5x=5x=5 and y=3

Solve the following equations by substitution method.
$x = 2 y - 1; y = 2 x - 7$

The correct option is C $x = 5, y = 3$
$x = 2 y - 1; y = 2 x - 7$
$x = 2 y - 1$ Put it in second equation.
$y = 2 \times (2 y - 1) - 7$
$y = 4 y - 9$
$y = 3$
and
$x = 2 y - 1 = 2 \times 3 - 1 = 5$
$x = 5$
$x = 5 a n d y = 3$