wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equations :
xaba+b+xaca+c+xbcb+c = a+ b + c

Open in App
Solution

The equation can be written as
(xaba+bc)+(xaca+cb)+(xbcb+ca) = 0
or xabbccaa+b+xabbccaa+c+xabbccab+c =0
(xabbcca)(1a+b+1a+c+1b+c) =0
Assuming (1a+b+1a+c+1b+c) 0,
x=ab+bc+ca as the root of the equation. If, however,
(1a+b+1a+c+1b+c) = 0, the given equation turns into an identity which holds for every value of x.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Framing a Linear Equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon