Solve the following equations- x2-12x-203x-5-x2-8x-122x-3

x ^ 2 +10x+2x 10 3x 5 = x ^ 2 +6x+2x+12 2x+3 (x+10)(x+2) (3x 5) = (x+6)(x+2) 2x+3 (x+2)≠ 0 (x+10)(2x+3)=(x+6)(3x 5) 2x^ 2 +3x+2 ...

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Solve the fol...

Question

Solve the following equations:
$\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}$

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\frac{x^{2} - 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{x^{2} + 12 x + 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{{(2 x + 1)}^{2} + {(2 x - 1)}^{2}}{{(2 x + 1)}^{2} - {(2 x - 1)}^{2}} = \frac{17}{8}

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

\frac{{(4 x + 1)}^{2} + {(2 x + 3)}^{2}}{4 x^{2} + 12 x + 9} = \frac{61}{36}

\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

(x^{2} + x + 1) + (x^{2} + 2 x + 3) + (x^{2} + 3 x + 5) + \dots \dots + (x^{2} + 20 x + 39) = 4500.

\sqrt{3 x - x^{2} - 5} = 2 x - 6

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