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Question

Solve the following equations :
xyay+bx=c,xzaz+cx=b,yzbz+cy=a.

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Solution

Rewriting the given equations, we get
ay+bxxy=1c,az+czxz=1b,bz+cyyz=1a
or ax+by=1c,ax+cz=1b,by+cz=1a.
Adding, ax+by=1c,ax+cz=1b,by+cz=1a.
Hence 2[ax+1a]=1a+1b+1c
or 2ax=1a+1b+1c2a=by+cz=1a,
x=2a2bcac+acab.
Similarly, y=2ab2cbc+abac
and z=2abc2bc+acab

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