Solve the following equations : xyay+bx=c,xzaz+cx=b,yzbz+cy=a.
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Solution
Rewriting the given equations, we get ay+bxxy=1c,az+czxz=1b,bz+cyyz=1a or ax+by=1c,ax+cz=1b,by+cz=1a. Adding, ax+by=1c,ax+cz=1b,by+cz=1a. Hence 2[ax+1a]=1a+1b+1c or 2ax=1a+1b+1c−2a=by+cz=1a, ∴x=2a2bcac+ac−ab. Similarly, y=2ab2cbc+ab−ac and z=2abc2bc+ac−ab