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Question

Solve the following equations.
2sin22x+6sin2x=5.

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Solution

2sin22x+6sin2x=5
8sin2x.cos2x+6sin2x=5
ut t=sin2x
8t(1t)+6t=5
8t8t2+6t=5
8t214t+5=0
8t210t4t+5=0
2t(4t5)1(4t5)=0
(2t1)(4t5)=0
t=1/2t=5/4
sin2x=1/2
sinx=±1/2
x=xπ+(1)n±π/4
=xπ±(1)nπ4
t=5/4
sinx=±52>1 hence no solution.
only solution is x=xπ±(1)nπ4;xϵz

1137995_888055_ans_c815b2f9a3b6416d82442d507e0376eb.jpg

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