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Question

Solve the following equations.
3logx+2logx1=2

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Solution

3logx+2logx1=2
3logx=22×12logx=2+logx
letlogx=z
3z=2+z
onsquaring,weget
3z=4+z2+4z
z25z+4=0
(z1)(z4)=04
z=1z=4
logx=1logx=4
x=ex=e4

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