Question

Solve the following equations.
$\frac{2x+1}{x}+\frac{4x}{2x+1}=5$

Answer 1

$\frac{2x+1}{x}+\frac{4x}{2x+1}=5$

$\frac{(2x+1{)}^2+4x^2}{(2x+1)\left(x\right)}=5$

$8x^2+1+4x=10x^2+5x$

$2x^2+x-1$=$0$

$2x^2-x+2x-1=0$

$x(2x-1)+1(2x-1)=0$

$(2x-1)(x+1)=0$

$(2x-1)=0$ and $(x+1)=0$

$x=\frac{1}{2}$ and $x=-1$