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Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
Solve the fol...
Question
Solve the following equations.
3
√
4
c
o
s
2
x
+
1
=
√
2
c
o
s
2
x
+
2
.
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Solution
3
√
4
c
o
s
2
x
+
1
=
√
2
c
o
s
2
x
+
2
3
=
√
8
c
o
s
2
2
x
+
10
c
o
s
2
x
+
2
3
=
√
8
(
1
−
2
s
i
n
2
x
)
2
+
10
(
1
−
2
s
i
n
2
x
)
+
2
[
∴
c
o
s
2
x
=
1
−
2
s
i
n
2
x
squaring both sides
a
=
20
+
32
s
i
n
4
x
−
52
s
i
n
2
x
take
s
i
n
2
x
=
t
then,
t
2
−
52
32
t
+
11
32
=
0
t
=
52
/
32
±
√
(
52
/
32
)
2
−
4
×
11
/
32
2
t
=
1.375
OR
0.25
s
i
n
2
x
=
1.375
OR
0.25
s
i
n
x
=
±
1.17
OR
±
0.5
s
i
n
x
=
±
1
/
2
x
=
π
/
6
,
2
π
/
3
,
7
π
/
6
,
5
π
/
3
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