Question

Solve the following equations.
${\left(\frac{5}{12}\right)}^x\cdot {\left(\frac{6}{5}\right)}^{x-1}=(0.3{)}^{-1}$

Answer 1

$(\frac{5}{12}{)}^x.(\frac{6}{5}{)}^{x-1}={0.3}^{-1}$

$\frac{5}{6}.\frac{1}{2^x}=\frac{10}{3}$

$2^{x+2}=1$

$⟹x+2=0⟹x=-2$