MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Substitution Method to Remove Indeterminate Form

Solve the fol...

Question

Solve the following equations.
$l o g_{2} s i n x - l o g_{2} c o s x - l o g_{2} (1 - t a n x) - l o g_{2} (1 + t a n x) = 1.$

Open in App

Solution

it can be written as

${log}_{2} \frac{s i n x}{c o s x (1 - t a n x) (1 + t a n x)} = {log}_{2} \frac{s i n x}{c o s x (1 - {t a n x}^{2})}$

therefore

$\frac{t a n x}{1 - (t a n x)^{2}}$ =2

solving we get

tanx= $\frac{(17)^{1 / 2} - 1}{4}$

Suggest Corrections

thumbs-up

0

Similar questions

{log}_{_{2}} (sin x) - {log}_{2} (cos x) - {log}_{2} (1 - tan x) - {log}_{2} (1 + tan x) = - 1

t a n 2 x =

Q. Solve the following equation find x

{log}_{4} (2 {log}_{3} (1 + {log}_{2} (1 + 3 {log}_{3} x))) = \frac{1}{2}

Q. Solve the following equation.

{log}_{1 / 2}^{2} (4 x) + {log}_{2} (\frac{x^{2}}{8}) = 8

: {log}_{2} (x - 1) + {log}_{2} (x + 1) = {log}_{2} 1

Q. Solve the following equations.

tan 3 x - tan x = 0.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Substitution Method to Remove Indeterminate Form

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Substitution Method to Remove Indeterminate Form

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon