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Question

Solve the following equations.
log2sinxlog2cosxlog2(1tanx)log2(1+tanx)=1.

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Solution

it can be written as

log2sinxcosx(1tanx)(1+tanx)=log2sinxcosx(1tanx2)

therefore

tanx1(tanx)2=2

solving we get

tanx=(17)1/214

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