Question

Solve the following equations.
${\log }_4{2}^{4x}=2^{{\log }_{2}4}$

Answer 1

$a^{lo{g}_a}b=b$

$⟹lo{g}_4{2}^{4x}=4$

$⟹2^{4x}=4^4=2^8$

$⟹x=2$