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Question

Solve the following equations.
sin4x3+cos4x3=58.

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Solution

sin4x3+cos4x3=58.
(sin2x/3)2+(cos2x/3)2+2sin2x/3.cos2x/32sin2x/3.cos2x/3=5/8
(sin2x/3+cos2x/3)22sin2x/3.cos2x/3=5/8
12sin2x/3cos2x/3=5/8
2sin2x/3cos2x/3=3/8
sin22x/32=3/8
1cos4x/34=38
cos4x/3=1/2
4x/3=±2π/3+2nπ
x=3xπ2±π2
nϵ integer

1137891_887888_ans_3b6544b122de434f8fe81a85b333ea55.jpg

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