wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equations.
sin4x3+cos4x3=58.

Open in App
Solution

sin4x3+cos4x3=58.
(sin2x/3)2+(cos2x/3)2+2sin2x/3.cos2x/32sin2x/3.cos2x/3=5/8
(sin2x/3+cos2x/3)22sin2x/3.cos2x/3=5/8
12sin2x/3cos2x/3=5/8
2sin2x/3cos2x/3=3/8
sin22x/32=3/8
1cos4x/34=38
cos4x/3=1/2
4x/3=±2π/3+2nπ
x=3xπ2±π2
nϵ integer

1137891_887888_ans_3b6544b122de434f8fe81a85b333ea55.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Transformations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon