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Forming Equation from Solution

Solve the fol...

Question

Solve the following equations.

(i) 4(x + 12) = 8 (ii) 3y + 4 = 5y $-$ 6

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Solution

(i)
4(x + 12) = 8
⇒ 4x + 48 = 8
⇒ 4x + 48 − 48 = 8 − 48
⇒ 4x = − 40
⇒ x = − 10
(ii)
3y + 4 = 5y − 6
⇒ 3y + 4 − 5y = 5y − 6 − 5y
⇒ 4 − 2y = − 6
⇒ 4 − 2y − 4 = − 6 − 4
⇒ − 2y = − 10
⇒ y = 5

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\frac{x}{3} + \frac{y}{4} = 4; \frac{x}{2} - \frac{y}{4} = 1

\frac{x}{3} + 5 y = 13; 2 x + \frac{y}{2} = 19

\frac{2}{x} + \frac{3}{y} = 13; \frac{5}{x} - \frac{4}{y} = - 2

4 x - 5 y = 6; 3 y - x = 2

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3 x - 4 y = 7; 5 x + 2 y = 3

5 x + 7 y = 17; 3 x - 2 y = 4

x - 2 y = - 10; 3 x - 5 y = - 12

4 x + y = 34; x + 4 y = 16

Solve the following system using Cramer’s Rule.

$- 4 x + 3 y = - 4$

- 8 x + 5 y = 0

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