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Question

Solve the following equations using factorization method.
(i) x23x10=0
(ii) 2x2+x6=0
(iii) 2x2+7x+52=0
(iv) 2x2x+18=0
(v) 100x220x+1=0

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Solution

i)x23x10=0x25x+2x10=0x(x5)+2(x5)=0(x5)(x+2)(x5)=0 or (x+2)=0x=5,2ii)2x2+x6=02x2+4x3x6=02x(x+2)3(x+2)=0(2x3)(x+2)=0(2x3)=0 or (x+2)=0x=32,2iii)2x2+7x+52=02x2+5x+2x+52=0x(2x+5)+2(2x+5)=0(x+2)(2x+5)=0(x+2)=0 or (2x+5)=0x=2,52iv)2x2x+18=016x28x+1=0(4x)22.4x+(1)2=0(4x1)2=0x=14v)100x220x+1=0100x210x10x+1=010x(10x1)1(10x1)=0(10x1)(10x1)=0(10x1)2=0x=110


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