Question

Solve the following equations without transposing and check your result.
$3x+4=19$

Answer 1

Take LHS of the given equation $3x+4=19$ and put $x=1,2,3,\cdots$.

$3\left(1\right)+4=7$

$\ne RHS$

$3\left(2\right)+4=10$

$\ne RHS$

$3\left(3\right)+4=13$

$\ne RHS$

$3\left(4\right)+4=16$

$\ne RHS$

$3\left(5\right)+4=19$

$=RHS$

Therefore, the value of $x$ is 5.