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Question

Solve the following equations:
x42x312x2+10x+3=0.

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Solution

Given equation, x42x312x2+10x+3=0

Consider f(x)=x42x312x2+10x+3

By inspection we can easily see that f(1)=0. Therefore, (x1) is one factor of the given equation

f(x)=(x1)g(x)g(x)=x3x213x3

We need to find root of g(x)=0

x3x213x3=0x3+3x24x212xx3=0(x+3)(x24x1)=0

Solving the quadratic equations, we have x=2±5

The roots of the given equation are x=1,3,2±5


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