Given: x4 – 3x2 + 2 = 0
Let x2 = m. Then, the equation can be written as:
m2 – 3m + 2 = 0
On splitting the middle term –3m as –m – 2m, we get:
m2 – m – 2m + 2 = 0
m(m – 1) –2(m – 1) = 0
(m – 1)(m – 2) = 0
m – 1 = 0 or m – 2 = 0
m = 1 or m = 2
On substituting m = x2, we get:
x2 = 1 or x2 = 2
x = ±1 or x = ±
Thus, the solutions of the given equation are ±1 and ±.