Question 97

Solve the following:

Find the product of the cube of (-2) and the square of (+4).

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Solution

$∵$ Cube of $(- 2) = (- 2)^{3}$
and square of $(+ 4) = (+ 4)^{2}$
$∴$ The product $= (- 2)^{3} \times (4)^{2} = (- 8) \times 16 = - 128$

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Question 97 Solve the following: Find the product of the cube of (-2) and the square of (+4).

∵ Cube of (−2)=(−2)3 and square of (+4)=(+4)2 ∴ The product =(−2)3×(4)2=(−8)×16=−128

Question 97

Solve the following:

Find the product of the cube of (-2) and the square of (+4).

$∵$ Cube of $(- 2) = (- 2)^{3}$
and square of $(+ 4) = (+ 4)^{2}$
$∴$ The product $= (- 2)^{3} \times (4)^{2} = (- 8) \times 16 = - 128$