Question 63
Solve the following:
12(x+1)+13(x−1)=512(x−2)
Given, 12(x+1)+13(x−1)=512(x−2)⇒x2+12+x3−13=512(x−2)⇒x2+x3−5x12=13−12−56⇒6x+4x−5x12=2−3−56⇒5x12=−66⇒5x×6=(−6)×12⇒x=(−6)×125×6∴x=−125
Question 65
2x−15=3x+13