Question 74
Solve the following:
3t−23+2t+32=t+76
Given, 3t−23+2t+32=t+76⇒2(3t−2)+3(2t+3)6=6t+76⇒6t−4+6t+9=6t+7⇒12t−6t=7−5⇒6t=2⇒t=26∴t=13