Question

Question 68

Solve the following:

$\frac{3t+5}{4}-1=\frac{4t-3}{5}$

Answer 1

Given, $\frac{3t+5}{4}-1=\frac{4t-3}{5}\Rightarrow \frac{3t+5-4}{4}=\frac{4t-3}{5}\Rightarrow 5(3t+1)=4(4t-3)\Rightarrow 15t+5=16t-12\Rightarrow 15t-16t=-12-5\Rightarrow -t=-17\Rightarrow \frac{-t}{-1}=\frac{-17}{-1}\therefore t=17$