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Method of Substitution to Find the Solution of a Pair of Linear Equations

Question 71 S...

Question

Question 71

Solve the following:

$\frac{9 - 3 y}{1 - 9 y} = \frac{8}{5}$

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Solution

Given, $\frac{9 - 3 y}{1 - 9 y} = \frac{8}{5} \Rightarrow 5 (9 - 3 y) = 8 (1 - 9 y) \Rightarrow 45 - 15 y = 8 - 72 y \Rightarrow 72 y - 15 y = 8 - 45 \Rightarrow 57 y = - 37 \Rightarrow \frac{57 y}{57} = \frac{- 37}{57} ∴ y = \frac{- 37}{57}$

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Question 71

Solve the following:

$\frac{9 - 3 y}{1 - 9 y} = \frac{8}{5}$

(1 - 9 y) \div (11 - 3 y) = \frac{5}{8} .

Solve the following equations and verify your answer :

$\frac{1 - 9 y}{19 - 3 y} = \frac{5}{8}$

Q. Solve the given equation for

y

\frac{1 - 9 y}{19 - 3 y} = \frac{5}{8}

.

Solve (i) (3x + 24) / (2x + 7) = 2: (ii) (1 − 9y) / (11 − 3y) = (5/8).

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Method of Substitution to Find the Solution of a Pair of Linear Equations

Standard X Mathematics

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