Solve the following- i -16 -5 ii 72 -12 iii -24 - 2 -iv 125 - 5 v -104 -13 vi 25 -4

(i) nbsp; #160;16 #160; #215; #160; #160;5=80 nbsp; nbsp; (ii) nbsp;72 #160; #247; #160; #160;12= 6 nbsp; nbsp; nbsp; ...

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Byju's Answer

Standard VII

Mathematics

Using Brackets

Solve the fol...

Question

Solve the following.

(i) $(- 16) \times (- 5)$ (ii) $(72) \div (- 12)$ (iii) $(- 24) \times (2)$

(iv) $125 \div 5$ (v) $(- 104) \div (- 13)$ (vi) 25 $\times (- 4)$

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Solution

(i) $(- 16) \times (- 5) = 80$

(ii) $(72) \div (- 12) = - 6$

(iii) $(- 24) \times (2) = - 48$

(iv) $125 \div 5 = 25$

(v) $(- 104) \div (- 13) = 8$

(vi) $25 \times (- 4) = - 100$

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Similar questions

Q. Which ratio is larger in the following pairs?
(i) 3 : 4 or 9 : 16
(ii) 15 : 16 or 24 : 25
(iii) 4 : 7 or 5 : 8
(iv) 9 : 20 or 8 : 13
(v) 1 : 2 or 13 : 27

Q. Express each one of the following with rational denominator:

(i)

\frac{1}{3 + \sqrt{2}}

(ii)

\frac{1}{\sqrt{6} - \sqrt{5}}

(iii)

\frac{16}{\sqrt{41} - 5}

(iv)

\frac{30}{5 \sqrt{3} - 3 \sqrt{5}}

(v)

\frac{1}{2 \sqrt{5} - \sqrt{3}}

(vi)

\frac{\sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3}}

(vii)

\frac{6 - 4 \sqrt{2}}{6 + 4 \sqrt{2}}

(viii)

\frac{3 \sqrt{2} + 1}{2 \sqrt{5} - 3}

(ix)

\frac{b^{2}}{\sqrt{a^{2} + b^{2}} + a}

Without actual division, find which of the following rational numbers are terminating decimals. (i) $\frac{13}{80}$ (ii) $\frac{7}{24}$ (iii) $\frac{5}{12}$ (iv) $\frac{31}{375}$ (v) $\frac{16}{125}$

Q. Solve the following equations.
(i)

{log}_{2} x = \frac{1}{2}

(ii)

{log}_{\frac{1}{5}} x = 3

(iii)

{log}_{3} y = - 2

(iv)

{log}_{x} 125 \sqrt{5} = 7

(v)

{log}_{x} 0.001 = - 3

(vi)

x + 2 {log}_{27} 9 = 0

Q. Write each of the following as percent:
(i)

\frac{7}{25}

(ii)

\frac{14}{625}

(iii)

\frac{5}{8}

(iv) 0.8
(v) 0.005
(vi) 3 : 25
(vii) 11 : 80
(viii) 111 : 125
(ix) 13 : 75
(x) 15 : 16
(xi) 0.18
(xii)

\frac{7}{125}

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Solve the following. (i) - 16 × - 5 (ii) 72 ÷ - 12 (iii) - 24 × 2 (iv) 125 ÷ 5 (v) - 104 ÷ - 13 (vi) 25 × - 4

(i) - 16 × - 5=80 (ii) 72 ÷ - 12=-6 (iii) - 24 × 2=-48 (iv) 125 ÷ 5=25 (v) - 104 ÷ - 13=8 (vi) 25× - 4=-100

Solve the following.

(i) $(- 16) \times (- 5)$ (ii) $(72) \div (- 12)$ (iii) $(- 24) \times (2)$

(iv) $125 \div 5$ (v) $(- 104) \div (- 13)$ (vi) 25 $\times (- 4)$

(i) $(- 16) \times (- 5) = 80$

(ii) $(72) \div (- 12) = - 6$

(iii) $(- 24) \times (2) = - 48$

(iv) $125 \div 5 = 25$

(v) $(- 104) \div (- 13) = 8$

(vi) $25 \times (- 4) = - 100$