Question

Solve the following -
i) $\sqrt[3]{35\frac{23}{64}}$
ii) $\sqrt[3]{327\times (-512)}$
iii) $\sqrt[3]{30.216}$
iv) $\sqrt[3]{3110592}$

Answer 1

i) $\sqrt[3]{35\frac{25}{64}}=\sqrt[3]{3\frac{347}{64}}=\frac{7}{4}$

ii) $\sqrt[3]{327\times (-512)}=3\times -8=-24$

iii) $\sqrt[3]{301216}1000=\frac{6}{10}=0.6$

iv) $\sqrt[3]{3110592}=\sqrt{2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 6\times 6\times 6}$

$=2\times 2\times 2\times 6$

$=8\times 6$

$=48$