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Question

Solve the following inequalities:
2xx20

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Solution

Given inequality is 2xx20
x2+x20
x2+2xx2<0
x(x+2)1(x+2)<0
(x+2)(x1)<0
(x+2)>0 and (x1)<0 or x+2<0 and x1>0
x<2 and x<1
2<x<1
Hence, x(2,1)

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