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Question

Solve the following inequalities.
2Cn5>11Cn23,nϵN

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Solution

2Cn5>11Cn23,nϵN
2×n(n1)(n2)(n3)(n4)5×4×3×2×1>11×(n2)(n3)(n4)3×2×1
2n(n1)20>11
n(n1)>110
n2n110>0
(n11)(n+10)>0
nϵ(,10)(11,)

1170523_883878_ans_b6ca7dbf29b24d6e9f6496ad000f98f1.jpg

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