Question

Solve the following inequalities.
$\frac{1}{lo{g}_{3}x}<1.$

Answer 1

$\frac{1}{{\log }_{3}x}<1$

And, $x>0$

and ${\log }_{3}x\ne 0⟹x\ne 1$

$⟹{\log }_{3}x>1$

$⟹x>3$