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Byju's Answer
Standard XII
Mathematics
Combination
Solve the fol...
Question
Solve the following inequalities
x
+
1
x
+
5
+
x
x
−
1
<
2
x
2
+
5
x
x
2
+
4
x
−
5
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Solution
x
+
1
x
+
5
+
x
x
−
1
<
2
x
2
+
5
x
x
2
+
4
x
−
5
⇒
x
2
−
1
2
+
x
(
x
+
5
)
(
x
+
5
)
(
x
−
1
)
<
2
x
2
+
5
x
x
2
+
4
x
−
5
⇒
x
2
−
1
+
x
2
+
5
x
x
2
+
4
x
−
5
<
2
x
2
−
5
x
x
2
+
4
x
−
5
⇒
2
x
2
+
5
x
−
1
<
2
x
2
+
5
x
⇒
−
1
<
0
which is true
∀
x
ϵ
R
.
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