Question

Solve the following inequalities.
$\frac{x^2+4}{x^2+7x+12}<0$

Answer 1

$\frac{x^2+4}{x^2+7x+12}<0$

Since, $x^2+4>0\forall x\in R$

$⟹x^2+7x+12<0$

$⟹(x+3)(x+4)<0$

$⟹-4<x<-3$ that is $x\in (-4,-3)$