Question

Solve the following inequalities.
$x+\frac{1}{x}<0$

Answer 1

$x+\frac{1}{x}<0$

$⟹\frac{x^2+1}{x}<0$

Since, $x^2+1>0\forall x\in R$

$⟹x<0$

Solution set-

$x\in (-\infty ,0)$