Question

Solve the following inequality:
$1+\frac{12}{x^2}<\frac{7}{x}$

Answer 1

$1+\frac{12}{x^2}<\frac{7}{x}1+\frac{12}{x^2}-\frac{7}{x}<0\frac{x^2-7x+12}{x^2}<0\frac{(x-4)(x-3)}{x^2}<0x\in (3,4)$