Question

Solve the following inequality:
$2\sqrt{x-1}<x.$

Answer 1

$2\sqrt{x-1}<x$

$x-1\ge 0$

$x\ge 1$

$xϵ[1,\infty )$

$2\sqrt{x-1}<x$

Squarring both sides

$4(x-1)<x^2$

$x^2-4x+4>0$

$(x-2{)}^2>0$

$xϵ(2,\infty )$