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Question

Solve the following inequality:
4x22(x1)+82(x2)3>52

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Solution

4x22(x1)+82(x2)3>52
(2x)2(2x2)2+(2x4)2>52
let2x=t
t2+t216t24>52
t2(1+11614)52>0
t2(1316)>52
t2>64
tε(8,)
2xε(8,)
xε(3,)

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