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Standard Equation of Parabola

Solve the fol...

Question

Solve the following inequality:
$(a + 1) \sqrt{2 - x} < 1.$

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Solution

$(a + 1) \sqrt{2 - x} < 1$
if $(a + 1) > 0 2 - x < \frac{1}{(a + 1)^{2}} x > 2 - \frac{1}{(a + 1)^{2}}$
if $(a + 1) < 0 x < 2 - \frac{1}{(a + 1)^{2}}$ .

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