MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Standard Equation of Parabola

Solve the fol...

Question

Solve the following inequality:
$(a + 1) \sqrt{2 - x} < 1.$

Open in App

Solution

$(a + 1) \sqrt{2 - x} < 1$
if $(a + 1) > 0 2 - x < \frac{1}{(a + 1)^{2}} x > 2 - \frac{1}{(a + 1)^{2}}$
if $(a + 1) < 0 x < 2 - \frac{1}{(a + 1)^{2}}$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following inequality:

\frac{x^{2} - 1}{x^{2} + x + 1} < 1

Q. Solve the following inequality:

\frac{1}{\sqrt{1 + x}} > \frac{1}{2 - x} .

Q. Solve the following inequality:

\frac{| x - 1 |}{x + 2} < 1

Q. Solve the following inequality:

\frac{1}{x - 2} + \frac{1}{x - 1} > \frac{1}{x}

Q. Solve the following inequality:

\frac{1}{x - 2} - \frac{1}{x} ⩽ \frac{2}{x + 2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Parabola

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard Equation of Parabola

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon