Question

Solve the following inequality:
$\frac{6x-5}{4x+1}<0$

Answer 1

$\frac{6x-5}{4x+1}<0$

$\frac{x-\frac{5}{6}}{x+\frac{1}{4}}<0$

$(x=0\frac{-5}{6}\times \frac{4}{1}<0)$

$x\epsilon (\frac{-1}{4},\frac{5}{6})$