Question

Solve the following inequality:
$\frac{1}{x-1}⩽2$

Answer 1

$\frac{1}{x-1}\le 2$

$\frac{1}{x-1}-2\le 0$

$\frac{1-2x+2}{x-1}\le 0$

$\frac{2x-3}{x-1}\ge 0$

$xϵ(-\infty ,1)\cup [\frac{3}{2},\infty )$