wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following inequality:
1+x2x25x+6<0

Open in App
Solution

1+x2x25x+6<0
As 1+x2>0xϵR
1x25x+6<0
1(x2)(x3)<0
xϵ(2,3)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon