Question

Solve the following inequality:
$\frac{17-15x-2x^2}{x+3}<0$

Answer 1

$\frac{17-15x-2x^2}{x+3}<0$

$\frac{2x^2+15x-17}{x+3}>0$

$\frac{2x^2+17x-2x-17}{x+3}>0$

$\frac{(x-1)(2x+17)}{x+3}>0$

$xϵ(\frac{-17}{2},-3)\cup (1,\infty )$