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Application of inequalities and absolute values

Solve the fol...

Question

Solve the following inequality:
$\frac{4 x + 3}{2 x - 5} < 6$

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Solution

$\frac{4 x + 3}{2 x - 5} < 6$
$\frac{4 x + 3}{2 x - 5} - 6 < 0$
$\frac{4 x + 3 - 12 x + 30}{2 x - 5} < 0$
$\frac{8 x - 33}{2 x - 5} < 0$
$x ϵ (\frac{5}{2}, \frac{33}{8})$

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Application of inequalities and absolute values

Standard XII Mathematics

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