Question

Solve the following inequality:
$\frac{(x-1)(x+2{)}^2}{-1-x}<0$

Answer 1

$\frac{(x-1)(x+2{)}^2}{-1-x}<0$

$\frac{(x-1)(x+2{)}^2}{x+1}>0$

$xϵ(-\infty ,-2)\cup (-2,-1)\cup (1,\infty )$