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Inequalities Involving Modulus Function

Solve the fol...

Question

Solve the following inequality:
$\frac{x - 1}{x + 3} > 2$

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Solution

$\frac{x - 1}{x + 3} > 2$
$\frac{x - 1}{x + 3} - 2 > 0$
$\frac{x - 1 - 2 x - 6}{x + 3} > 0$
$\frac{x + 7}{x + 3} < 0$
$x ϵ (- 3, - 7)$

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Inequalities Involving Modulus Function

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