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Concept of Inequality

Solve the fol...

Question

Solve the following inequality:
$\frac{x^{2} - 1}{2 x + 5} < 3$

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Solution

$\frac{x^{2} - 1}{2 x + 5} < 3$
$\frac{x^{2} - 1}{2 x + 5} - 3 < 0$
$\frac{x^{2} - 6 x - 16}{2 x + 5} < 0$
$\frac{(x - 8) (x + 2)}{2 x + 5} < 0$
$x ϵ (- \infty, \frac{- 5}{2}) \cup (- 2, 8)$

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