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Functions

Solve the fol...

Question

Solve the following inequality:
$\frac{x^{2} + 2}{x^{2} - 1} < - 2$

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Solution

$\frac{x^{2} + 2}{x^{2} - 1} < - 2 \frac{x^{2} + 2}{x^{2} - 1} - 2 < 0 \frac{3 x^{2}}{x^{2} - 1} < 0 \frac{x^{2}}{(x - 1) (x + 1)} < 0 x \in (- 1, 1) - {0}$

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