Question

Solve the following inequality:
$\frac{x^2-5x+6}{x^2+x+1}<0$

Answer 1

$\frac{x^2-5x+6}{x^2+x+1}<0$

As discriminant of $x^2+x+1$ less than $0$, So, $x^2+x+1>0\forall xϵR$

$x^2-5x+6<0$

$(x-2)(x-3)<0$

$xϵ(2,3)$