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Question

Solve the following inequality:
x2|x|12x32x

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Solution

x0
x2x12x32x0
x2+5x12x30
x25x+12x30
1x30
x(0,3)
And
x<0
x2+x12x32x0
x2+7x12x30
x27x+12x30
(x3)(x+4)x30
(x+4)0
x(,4)
x(0,3)(,4)

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