Question

Solve the following inequality:
$\frac{x^2-x-6}{x^2+6x}⩾0$

Answer 1

$\frac{x^2-x-6}{x^2+6x}\ge 0$

$\frac{(x-3)(x+2)}{x(x+6)}\ge 0$

$xϵ(-\infty ,-6)\cup [-2,0)\cup [3,\infty )$