Question

Solve the following inequality:
${\log }_{1/6}(x^2-3x+2)+1<0$

Answer 1

$-{\log }_6(x^2-3x+2)+1<0$

${\log }_6(x^2-3x+2)>1$

$x^2-3x+2>6$

$x^2-3x-4>0$

$(x-4)(x+1)>0$

$x\epsilon (-\infty ,-1)\bigcup (4,\infty )$