CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
15
You visited us 15 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following inequality:
log20.5x+log0.5x20

Open in App
Solution

log0.5x=log2x
letlog2x=z
+z2z20
(z2)(z+1)0
zε[1,2]
1z2
1log2x2
taking antilog,we get
12x4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon